Question
The tangential speed of a particle on a rotating wheel is $3.0 \mathrm{~m} / \mathrm{s}$. If the particle is $0.20 \mathrm{~m}$ from the axis of rotation, how long will the particle take to make one revolution?
Step 1
Step 1: We know that the tangential speed (v) of a particle on a rotating wheel is related to the angular speed (ω) and the distance from the axis of rotation (r) by the equation: \[v = rω\] We can rearrange this equation to solve for ω: \[ω = \frac{v}{r}\] Show more…
Show all steps
Your feedback will help us improve your experience
Narayan Hari and 71 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A particle moves 3.0 m along a circle of radius 1.5 m. (a) Through what angle does it rotate? (b) If the particle makes this trip in $1.0 \mathrm{s}$ at a constant speed, what is its angular velocity? (c) What is its acceleration?
The precession angular velocity of a gyroscope is 1.0 rad/s. If the mass of the rotating disk is $0.4 \mathrm{kg}$ and its radius is $30 \mathrm{cm},$ as well as the distance from the center of mass to the pivot, what is the rotation rate in rev/s of the disk?
Linear Speed. A wheel with a 30 -cm radius is rotating at a rate of 3 radians/sec. What is the linear speed of a point on its rim, in meters per minute?
The Trigonometric Functions
Radians, Arc Length, and Angular Speed
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD