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The temperature of a student's skin is $33.0^{\circ} \mathrm{C}$ . At what wavelength does the radiation emitted from the skin reach its peak?

9.47 \times 10^{-6} \mathrm{m}

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Cornell University

University of Washington

Hope College

University of Sheffield

So in this problem, we want to find the radiation wavelength for students skin. And so first, let's write down the temperature. Um, so is 33 degrees Calvin. And then if we want to get the R degrees Celsius and then we want to get the temperature and Calvin so we need to add to 73 to that. So that's 306 Calvin. And, um next What we want to do is use the wine's displacement law to get the wavelength. And that states that Lambda T is equal to 0.2898 times 10 to the minus two Calvin meter and then we can solve for Lambda. And then we got lambda by dividing both sides by t. So all this go ahead and sort of rewrite. The equations can do this one. So in this problem, we want to find the radiation wavelength for ah student skin. And so first, let's write down the temperature. Um, so was 33 degrees Calvin. And then if we want to get the r degrees Celsius and then we want to get the temperature and Calvin so we need to add to 73 to that. So that's 300 sex session. So playing that in to a calculator rat 9.47 microns so not energetic enough for the eye to detect, react to rely on the optical photons reflecting from skin, not there, not the temperature dependent radiation.

University of Washington