The temperature of sink of Carnot engine is 27^∘ C. Efficiency of engine is 25 % Then find the t

step 1 Hello friends the temperature of the sink of Carnot engine. Suppose this is a Carnot engine, it

The temperature of sink of Carnot engine is 27^∘ C....

The temperature of sink of Carnot engine is $27^{\circ} \mathrm{C}$. Efficiency of engine is $25 \%$ Then find the temperature of source.
(A) $227^{\circ} \mathrm{C}$
(B) $327^{\circ} \mathrm{C}$
(C) $27^{\circ} \mathrm{C}$
(D) $127^{\circ} \mathrm{C}$

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Key Concepts

Heat Reservoirs

Heat reservoirs are large systems that maintain a constant temperature during the energy exchange processes in a heat engine. The hot reservoir supplies thermal energy to the engine, while the cold reservoir absorbs the rejected heat. The temperatures of these reservoirs are crucial because they directly dictate the theoretical maximum efficiency of the engine as determined by the Carnot cycle.

Carnot Engine Efficiency

This concept refers to the maximum theoretical efficiency that any heat engine operating between two temperatures can achieve. The efficiency is determined solely by the temperatures of the heat reservoirs and is given by the formula ? = 1 - (T_cold/T_hot), with temperatures in Kelvin. This efficiency represents the ideal limit under reversible processes, highlighting the fundamental constraints imposed by the second law of thermodynamics.

Absolute Temperature Scale

In thermodynamics, it is essential to use an absolute temperature scale, such as Kelvin, for accurate calculations. The Kelvin scale starts from absolute zero, ensuring that all thermodynamic computations, including those involving efficiency, are physically valid. This conversion from Celsius to Kelvin is achieved by adding 273.15, a necessary step when applying formulas that rely on absolute temperatures.

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