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The temperature of the cooling water as it leaves the hot engine of an automobile is $240^{\circ} \mathrm{F}$ . After it passes through the radiator it has a temperature of $175^{\circ} \mathrm{F}$ . Calculate the amount of heat transferred from the engine to the surroundings by one gallon of water with a specific heat of 4.184 $\mathrm{J} / \mathrm{g}^{\circ} \mathrm{C}$ .

1 gallon of cooling water released $571,7 \mathrm{kJ}$ of heat from engine to surroundings.$$q=-57.7 \mathrm{kJ}$$

Chemistry 101

Chapter 5

Thermochemistry

Drexel University

Brown University

University of Toronto

Lectures

05:27

In chemistry, a chemical r…

06:42

In chemistry, energy is wh…

01:02

(I) An automobile cooling …

00:50

01:19

05:17

Water is used as the worki…

05:35

The cooling system of a ca…

04:21

04:19

Car Engine A $2.50 \times …

03:24

A Carnot engine has an eff…

06:25

A Carnot engine uses hot a…

00:51

Calculate the quantity of …

02:34

Calculate the amount of he…

01:48

If a reaction produces 1.5…

02:12

01:09

A 150.0 -g sample of a met…

03:18

A heat engine receives hea…

11:34

The motor that drives a re…

00:31

Calculate the amount of en…

01:36

Assume that the kinetic en…

01:08

(I) How much heat (in joul…

Ethylene glycol (HOCH,CH,O…

Okay. Why in this problem, we are trying to calculate the amount of heat released by this engine. Um, that heat is absorbed by water and then released to the surroundings. So this is a problem where we're trying to calculate the amount of energy, do that we're going to need the specific heat that is a constant, that we can look up for water in this case, since water is absorbing the energy and it will tell us the amount of energy in jewels for every gram degree, Celsius of the substance. So we're gonna take that specific heat and we need to multiply it by the number of grams of water we have or, in other words, the mass. And also multiply that by the change in temperature, how many degrees Celsius it changed. So in this problem, we are given a couple of temperatures are initial temperature and our final temperature, and they are both in degrees Fahrenheit. So what we need to do is convert these two Celsius. So our initial temperature, for example, is 240 degrees Fahrenheit. Using the equation where we take 5/9 times 3 F temperature minus 32 we will find that the equivalent Celsius temperature is 1 15.6 for our final temperature were given 175 F. Again using our equation. Where we take 5/9 the Fahrenheit temperature minus 32 I get a Celsius temperature of 79 0.4 degrees. All right, let's go ahead and set up our overall equation, then to calculate the amount of energy. Q. I need the specific heat for water. Since water is air substance here being used to absorb the heat, it is 4.184 Jules program degrees Celsius. Next, I need the mass of the water in Gramps. They tell us we have one gallon of water, so I need to do a little converting here. First thing I want to do. He's convert that gallon 2 mL in every gallon of anything. There's 3785 millimeters. I can then use the density of water. They tell us in this problem to assume 1 g per milliliter as the density. If we do a little bookkeeping with our units, we see that gallon will cancel and militar will cancel and this will give us grams and finally I need to multiply by the change in temperature. So the T final is 79.4 degrees Celsius and subtract the initial temperature, all right, And we should be good to go. We can see that our masses and grams so that will cancel the unit grams and our temperature change is going to be in degrees Celsius. So that will cancel that. That means when I calculate this answer, I am going to get a value that is in the units jewels. And it's gonna be negative telling us that that energy is being released. I get 57 3279 jewels. I'm gonna go ahead and divide that by 1000 to convert it to kill the jewels. So there are 1000 jewels in a killer. Jewell just doing this to make the answer a little more manageable. It's not changing the actual value. It's just changing the units. And that's going to give me 573 killer jewels of energy, which is our answer for this problem. That's the amount of energy that is released by the engine absorbed by the water. Thank you for watching. Okay,

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