Question
The tension member is fastened together using two bolts, one on each side of the member as shown. Each bolt has a diameter of 0.3 in. Determine the maximum load $P$ that can be applied to the member if the allowable shear stress for the bolts is $\tau_{\text {allow }}=12 \mathrm{ksi}$ and the allowable average normal stress is $\sigma_{\text {allow }}=20 \mathrm{ksi}$
Step 1
The formula for the surface area of a circle is $A = \pi r^2$. Given that the diameter of the bolt is 0.3 in, the radius is $r = 0.3/2 = 0.15$ in. Therefore, the surface area of the bolt is $A = \pi (0.15)^2 = 0.0707$ in$^2$. Show more…
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The tension member is fastened together using two bolts, one on each side of the member as shown. Each bolt has a diameter of 0.3 in. Determine the maximum load $P$ that can be applied to the member if the allowable shear stress for the bolts is $\tau_{\text {allow }}=12 \mathrm{ksi}$ and the allowable average normal stress is $\sigma_{\text {allow }}=20 \mathrm{ksi}$.
L1 = 4 L2 = 7 (inch)
The hanger is supported using the rectangular pin. Determine the magnitude of the allowable suspended load $\mathbf{P}$ if the allowable bearing stress is $\left(\sigma_{b}\right)_{\text {allow }}=220 \mathrm{MPa}$, the allowable tensile stress is $\left(\sigma_{t}\right)_{\text {allow }}=150 \mathrm{MPa},$ and the allowable shear stress is $\tau_{\text {allow }}=130 \mathrm{MPa}$. Take $t=6 \mathrm{mm}$ $a=5 \mathrm{mm}$ and $b=25 \mathrm{mm}$
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