Question
The three points given form a right triangle. Find the midpoint of the hypotenuse and verify that the midpoint is an equal distance from all three vertices.$$\begin{aligned}&P_{1}=(6,-6)\\&P_{2}=(-12,18)\\&P_{3}=(20,42)\end{aligned}$$
Step 1
The midpoint of a line segment with endpoints $(x_1, y_1)$ and $(x_2, y_2)$ is given by $\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$. So, the midpoint of the hypotenuse is $\left(\frac{-12+20}{2}, \frac{18+42}{2}\right) = (4, 30)$. Show more…
Show all steps
Your feedback will help us improve your experience
Harmender Singh Yadav and 87 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The three points given form a right triangle. Find the midpoint of the hypotenuse and verify that the midpoint is an equal distance from all three vertices. $$\begin{aligned}&P_{1}=(10,-21)\\&P_{2}=(-6,-9)\\&P_{3}=(3,3)\end{aligned}$$
Analytical Geometry and the Conic Sections
A Brief Introduction to Analytical Geometry
The three points given form a right triangle. Find the midpoint of the hypotenuse and verify that the midpoint is an equal distance from all three vertices. $$\begin{aligned}&P_{1}=(0,-5)\\&P_{2}=(-6,4)\\&P_{3}=(6,-1)\end{aligned}$$
The three points given form a right triangle. Find the midpoint of the hypotenuse and verify that the midpoint is an equal distance from all three vertices. $$\begin{aligned}&P_{1}=(-5,2)\\&P_{2}=(1,2)\\&P_{3}=(-5,-6)\end{aligned}$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD