00:03
Okay, this is going to be a bit of a longer one because it's given us a pretty big formula.
00:09
We've got c -15 -h -11 n -o -4 -i -4.
00:20
Okay, and it wants to know what the percent composition is of each of those elements in this formula by mass.
00:28
Okay, so just like the other present composition questions we've done, the first thing we've got to do here is add up the total molar mass of this compound, and we're going to do it by breaking it down into the individual elements.
00:42
So we're going to say carbon, hydrogen, nitrogen, oxygen, and iodine.
00:50
If we look on the periodic table, we can see that carbon has a molar mass or atomic weight of 12.
00:58
You look right here.
01:00
Okay, hydrogen is one, oxygen is 16, nitrogen is 14, so they're all pretty common.
01:10
The one that you might have a harder time remembering is iodine, which is 127.
01:18
Okay, so let's write all these down.
01:19
So hydrogen was one, nitrogen was 14, oxygen was 16, iodine was 127.
01:28
Then we're going to multiply each of these by how many of that element we have.
01:33
So the carbon gets multiplied by 15, hydrogen by 11, nitrogen, there's just one of because there's no subscript there, oxygen times 4, and iodine times 4.
01:45
So a couple of these are going to be simpler than the others.
01:53
These other two we might have to bust out our calculator for.
01:58
12 times 15 is 180, and then 127 times 4 is 508.
02:08
So up here for the carbon, we would have 180...