The time integral of a torque is called the angular impulse. ( $a$ ) Starting from $\overrightarrow{\boldsymbol{\tau}}=d \overrightarrow{\mathbf{L}} / d t$, show that the resultant angular impulse equals the change in angular momentum. This is the rotational analogue of the linear impulse-momentum relation.
(b) For rotation around a fixed axis, show that
$$
\int \tau d t=F_{\mathrm{av}} r(\Delta t)=I\left(\omega_{\mathrm{f}}-\omega_{\mathrm{i}}\right)
$$
where $r$ is the moment arm of the force, $F_{\mathrm{av}}$ is the average value of the force during the time it acts on the object, and $\omega_{\mathrm{i}}$ and $\omega_{\mathrm{f}}$ are the angular velocities of the object just before and just after the force acts.