00:01
Okay, so we're given a normal distribution with the mean of 10 and a standard deviation of 2.
00:06
And what we're trying to find is the probability that the mean x value is at most 11 over two different days.
00:14
And so what i'm going to do is cut this up into day one and day two and find the probabilities on day 1 and day 2 and then go from there.
00:24
So on day one, we have five people filling out the form.
00:30
N is equal to 5.
00:31
And what i'm going to do is use something called a z score, which basically just transforms our normal distribution into the standard normal distribution, and transforms our maximum value or 11, into whatever that value would be on the standard distribution table.
00:50
So then we can just look at that table to find our probabilities.
00:53
So the z score is the mean x value minus our u value, divided by the standard deviation divided by the square root of the number of trials or of n.
01:08
And so if i do this for 11, we would have 11 minus 10 divided by our standard deviation, which is 2, divided by square root of 5, since we have 5 trials.
01:25
And this is equal to 1 over 2 divided by the square of 5 and now you can just simplify this to square to 5 over 2 and we can plug this into our probability so we say the probability of z being less than or equal to 1 sorry square to 5 over 2 this is equal to our probability of our x -main being less than equal to 11.
01:56
So now we can just use the standard normal distribution table to find our probability.
02:04
And so the last thing we're going to want to do is actually divide our square root of 5 by 2.
02:13
So we have a value to look at for the standard distribution table, standard normal distribution table.
02:21
So this is square to 5 over 2 is equal to 1 .1...