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### A child is born with an imperforate anus, in whic…

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Problem 10
Chapter 1
Section
Johns Hopkins University

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Problem 9

The total area of a coastal city is 92.1 square miles, of
which 11.3 square miles is water. If the city had a
population of $621,000$ people in the year $2010,$ which
of the following is closest to the population density,
in people per square mile of land area, of the city at
that time?
$$\begin{array}{ll}{\text { A) }} & {6,740} \\ {\text { B) }} & {7,690} \\ {\text { C) }} & {55,000} \\ {\text { D) }} & {76,000}\end{array}$$

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SAT
SAT Practice Test # 6

## Discussion

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## Video Transcript

So for this one, let's just say that here is our crystal City and is ninety two point one square miles. But then there is Let's just say that there was a lake or something that's in the middle of the city, and it takes up eleven point three excrement. So then, if we have a population, those sixty six hundred twenty one thousand, well, they can only live in this green area because they can only live on land. People can't just float on water, so we know that we have to subtract the amount of water. So then we're going to do ninety two point one, minus eleven point three initially to seeing how many square miles are available for people to actually want. So that's going to be eighty point eight. So we know that eighty point eight is the square miles that people can actually live on, and then if we have six hundred twenty one people, but we want to know that people per per square mile, we just have to take the six hundred twenty one people and divide that by square miles, which is eighty point eight miles squared. You do six hundred twenty one thousand. To find a type of eighty point eight, it's going to be seven thousand six hundred eighty six, so that's roughly about seven thousand six hundred ninety b.