To do this, we need to integrate the rate function R(t) with respect to time t from 0 to 6:
$$
\int_0^6 R(t) dt = \int_0^6 (2.718t^2 - 19.86t + 50.18) dt
$$
Now, we can integrate each term separately:
$$
\int_0^6 2.718t^2 dt - \int_0^6 19.86t dt + \int_0^6
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