00:02
In this problem, we have a triple jump athlete who is approaching the takeoff line with a constant horizontal velocity.
00:12
They take off at a given angle and a given velocity, and we want to calculate the vertical component of the average impulsive force exerted by the ground on the foot of the athlete.
00:24
So if we look at our impulse momentum diagram, we see initially the athlete has horizontal momentum, mv1, due to their horizontal velocity.
00:33
At the time of launch, the impulses acting on the foot are due to p, which is the ground on the foot, which we wish to calculate, and the weight of the athlete acting downwards.
00:51
The final momentum of the athlete is at an angle of 50 degrees, and it's m v2.
00:58
So writing this mathematically, we have mv1 plus the impulse p minus w since the athlete takes off in a time of impact, delta t, must equal to the final momentum of the athlete mv2.
01:25
So if we look at this equation and we take vertical or y components, we can write it as follows...