Question
The turbines in a hydroelectric plant are fed by water falling from a 50 -m height. Assuming $91 \%$ efficiency for conversion of potential to electrical energy, and $8 \%$ loss of the resulting power in transmission, what is the mass flowrate of water required to power a $200 \mathrm{W}$ light bulb?
Step 1
Assuming we have 1 kg of water, $g = 9.81 \, m/s^2$, and $h = 50 \, m$, we find that $PE = 1 \, kg \cdot 9.81 \, m/s^2 \cdot 50 \, m = 490.5 \, J$. Show more…
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The turbines in a hydroelectric plant are fed by water falling from a 50 m height. Assuming 91% efficiency for conversion of potential to electrical energy, and 8% loss of the resulting power in transmission, what is the mass flow rate of water required to power a 200 W light bulb
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