00:02
In this problem, we have two blocks a and b, which have identical mass, and are suspended from parallel chords.
00:09
A spring with a known spring constant is attached between the blocks, and the blocks are initially at rest with the spring compressed.
00:17
We want to calculate the maximum angles of the chords when the blocks are released from rest.
00:24
So if we take block a as an example, its angle is theta when it reaches its highest point, its lowest point will regard as the datum.
00:33
The string or the cord has length to meters.
00:38
So its maximum height, when theta is in a maximum for block a is the same as the maximum height for block b at an angle of phi is 2 minus 2 cost theta.
00:52
So the first thing we will do is apply the conservation of linear momentum in the horizontal direction.
01:00
So the conservation of linear momentum tells us that the sum of the momenta before must equal to the sum of the momentum after.
01:15
Now initially both the blocks are addressed.
01:17
So they have no momentum.
01:19
So the initial momentum of the system is zero.
01:22
And the final momentum of the system, we take the right as positive, is equal to the mass of block a times its velocity after it begins to move apart.
01:36
Plus the mass of block b, which is also 5kg times its velocity vb.
01:43
So we can see that va is equal to vb, and we'll call this velocity v or the speed v.
01:52
So that's the speed at which these two blocks will begin to move apart when they are released from rest.
01:59
Now we apply the conservation of momentum.
02:02
Next we'll apply the conservation of energy.
02:05
Now the conservation of mechanical energy tells us that the initial kinetic plus gravitational potential energy of the two blocks must equal their final kinetic and gravitational potential energies.
02:20
So t1 plus v1 must equal to t2 plus v2.
02:26
Now this is just before the blocks begin to rise.
02:32
So initially we have no kinetic energy for either block.
02:44
We have no gravitational potential energy but we have potential energy stored in the spring.
02:49
That's a half kx squared.
02:52
So it's a half times 60 times the compression, which is 0 .3 meters...