00:01
So in this problem, we have two blocks that are shown initially at rest, and we want to neglect the mass of the pulleys, the effect of friction in the pulleys, and the friction between block a and the incline.
00:10
And we want to find a, the acceleration of each block, and b the tension of the cable.
00:16
So the two blocks are shown initially at rest was in the figure, and we're given that the weight of block a is 200 pounds.
00:26
The weight of b is 300 pounds.
00:30
So to calculate the acceleration of each block and the tension is the tension is, you know, the cable, we have to first write the equation of the dependent motion between the two blocks is followed.
00:38
So we can see that that would be x of a minus 2y with b is equal to constant.
00:47
And then we want to take the derivative with respect to time to get the velocity, which will just leave us with b a minus 2 v b is equal to 0, and then we can take the derivative with time again to get the acceleration, which will give us acceleration of a minus 2, ab is equal to 0.
01:20
And here we can solve for the acceleration in b, which is just one half, the acceleration of a.
01:26
And we'll call this equation 1.
01:28
So now we want to draw a free body diagram and a kinetic diagram for each block to illustrate the forces acting on each block and the acceleration vector.
01:36
We can do this by looking at the figure and applying newton's law using equation 12 .8...