The two cylindrical rod segments are fixed to the rigid walls such that there is a gap of 0.01 in. between them when $T_{1}=60^{\circ} \mathrm{F}$. Each rod has a diameter of 1.25 in. Determine the average normal stress in each rod if $T_{2}=400^{\circ} \mathrm{F},$ and also calculate the new length of the aluminum segment. Take $\alpha_{\mathrm{al}}=13\left(10^{-6}\right) /^{\circ} \mathrm{F}, E_{\mathrm{al}}=10\left(10^{3}\right) \mathrm{ksi}$
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\left(\sigma_{Y}\right)_{\mathrm{al}}=40 \mathrm{ksi}, \alpha_{\mathrm{cu}}=9.4\left(10^{-6}\right) /^{\circ} \mathrm{F},\left(\sigma_{Y}\right)_{\mathrm{cu}}=50 \mathrm{ksi}, \text { and } \\
E_{\mathrm{cu}}=15\left(10^{3}\right) \mathrm{ksi}
\end{array}