00:01
The two forces, f1 and f2 shown in figure 440a and b, looking down, octa on an 18 and a half kilogram object on a frictionless tabletop.
00:10
If f1 is 10 .2 newtons and f2 16 newtons, find the net force on the object in the acceleration for both a and b.
00:22
So for a, i were asked to find the sum of the two forces and the acceleration of an 18 and a half kilogram valve, what it would experience.
00:34
So we would know that the f1 would be 10 .2, f216 and the mass is 18 .5 kilograms.
00:47
So we want to find that some of the forces will use the total force is equal to the square root of the first force squared plus the second force squared.
01:02
And that would be the square root of 10 .2 squared plus 16 squared, which is about 18 .97.
01:30
Now finding the acceleration will use the total force to be equal to the mass times the acceleration.
01:45
And so that would be acceleration is the total force over the mass.
01:51
And if the total force is 18 .97 newtons with a mass of 18 .5 kilograms, we get about 1 .03.
02:06
Meters per second squared and the total force is about 19 newtons.
02:21
For part b we know that f1 again is 10 .2 newtons f2 is 16 newtons and that the mass is 18 .5 kilograms...