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University of Wisconsin - Milwaukee

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Problem 31 Medium Difficulty

The two lenses of a compound microscope are separated by a distance of 20.0 $\mathrm{cm}$ . If the objective lens produces a lateral magnification of $10.0 \times$ and the overall magnification is $115 \times$ determine (a) the angular magnification of the eyepiece, (b) the focal length of the eyepiece, and (c) the focal length of the objective lens.

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Top Physics 103 Educators
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Video Transcript

in this problem, we have the length of the microscope. That is the distance between the objective and I piss is 20. Senator, The lateral magnification of the objective is 10 and I'm using the negative side because the object is upside down, the image of the object is upside down, and the overall magnification of the microscope is 100 and 15. And I'm using negative sand just as the same reason for the lateral magnification. Okay, so in part A to find the angular magnification of the eyepiece. What we're gonna do is we're gonna use the definition for the lateral magnification, which is MM equals m one dot e. So from here, M e, which is the magnification of the eyepiece, is going to be him over and one, and that's going to be a negative 115 over negative 10. And this is going to give me 11.5. So this is the angular magnification of the apis. So for part B, to find the focal length of the eyepiece, we basically just use M e. The definition of the angler magnification for the I piss is going to be 25 centimeter over focal length of the eyepiece. And from here, F E is going to be 25 centimeter over M E. And we know at me. So 25/11 0.5 and this will give me 2.17 centimeter. So this is the focal length of the eyepiece. Now this go to Parsi, in which we are trying to find the objective for collect. So what we're gonna do is we're gonna use the definition of the lateral magnification of the objective, which is gonna be negative over focal length of the objective. And the focal length of the objective is going to be negative. Hell over M one and negative. L is negative. 20 centimeter over negative 10. So this will give me two centimeter.

University of Wisconsin - Milwaukee
Top Physics 103 Educators
Andy C.

University of Michigan - Ann Arbor

Marshall S.

University of Washington

Jared E.

University of Winnipeg

Meghan M.

McMaster University