00:01
In this question we have been given two metallic objects and the net charges at first.
00:05
So the initial net charge is given to us as 70 picolululums and the potential difference between the objects is given to us as 35 volts.
00:18
Now we have to find out the capacitance of this system in the first part of the question.
00:24
So in part a we have to find out what exactly is the capacitance of the system.
00:29
So we know that capacitance is a formula for capacitance can be, so we know q is equal to cv.
00:37
From here we can write c is equal to q upon v, which is potential difference.
00:44
And q is given to us as 70 picoculum.
00:46
So it's 70 into 10 raised to the power minus 12.
00:50
And the voltage across is given as 35.
00:53
So we can conclude by saying that the value of capacitance here is 2 pico ferrets.
00:59
So this is the answer for part a of the question.
01:02
Now let's move on to the second part of the question.
01:05
It says that now the charges become, so now q final becomes 200 picololol columns...