00:01
In this question, we have this robot bin that has a length of l and a mass of m.
00:08
But then when a force f is applied on one side of it, this stretches an additional length, delta l.
00:17
So we want to know first what is a wave that a wave will travel on it in terms of these numbers were given.
00:26
So in order to do that, we know that the wave, the speed of the speed of the wave of any wire is tension over linear density mu.
00:43
Well in here we know the total force is f.
00:48
So how do we find the tension in it? the force will be equal to the tension.
00:54
But we do not know what f is, but we know that this length is stretched by delta l and we know this wire has a hook's constant k.
01:03
So again from the previous chapter chapter 15, you know that a wire, a spring or any stretchable wire follow the rule that force equals negative kx.
01:15
So here the axis the delta l.
01:18
So tension equals k times delta l.
01:22
Mu is mass over less.
01:25
But here, the less is not l, the lens is l plus delta l because the lens is el...