00:02
In this given problem, positively charged uranium ions are coming out of the accelerating parallel plates.
00:17
These two equally and oppositely charged plates are being used to accelerate the uranium ions, positively charged ions.
00:33
Now these ions, this beam of ions is allowed to pass through a velocity selector.
00:42
Here this horizontal plate are used as a velocity selector through which this beam is passing undeflected.
00:53
In this region the magnetic field is uniform and coming out of the plane of paper.
01:03
Like this.
01:10
So magnetic field in the velocity selector is out of the plane of paper.
01:42
Now in the first part of the problem we have to find direction of electric field so that this beam of positively charged uranium ions remains may remain undeflected.
01:56
So first of all, here this is the direction of motion of the ions and these are the positively charged ions.
02:05
Velocity v and magnetic field is upward, outward, perpendicular to the plane of paper.
02:13
So using expression for magnetic laurence force experienced by these ions which are moving towards right.
02:25
And that expression for the magnetic lawrence force is f bar is equal to u into v cross b.
02:35
So using right -hand screw rule in this cross -product, we get direction of v cross -b, is the cross -product, and hence same will be the direction of force...