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The 10 -lb-uniform rod $A B$ has a total length o…

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Problem 117 Easy Difficulty

The uniform rod $A B$ with a mass $m$ and a length of $2 L$ is attached to collars of negligible mass that slide without friction along fixed rods. If the rod is released from rest in the position shown, derive an expression for ( $a$ ) the angular acceleration of the rod, ( $b$ ) the reaction at $A$

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Video Transcript

hello print, as during the figure you need from rod egg off must and and then you will the mark abroad. A V is given em on. Excellent is Who will right is attached to the colors off Negligible mask. That's the light without friction along the fixed. Brought If the rod is released from rest that a omega is zero in positions or in figured, we have to calculate angular acceleration and reaction at eight to calculate angular acceleration off the road. That is a V and reactions at eight. Let us hear the kinda. Meh ticks off the Lord. This is center off most of the rod. It's having acceleration ever. No, Never see it. Only guys given Jiro the acceleration off. It can be driven. ID acceleration off key plus acceleration off. Eight. Disrespectful G. So if this a is towards left uses a work is downward. Look. And l for that angle. Data with origin. Moment off. Energy of the road about the center off months, one by 12 off AM in tow. The square. It would be one y three. How many sweat? No. See the freeborn diagrams fdd off the road? Yeah, a point the point center off Mass G. Yeah. Fourth am Able Act? Yeah, the w will act. This is the reaction at eight and I into a helper speaking commission off foods along her gentle direction. This is the reaction at G Commission off epics. Taking a right to be positive you will get. These are 20 taking moment off course about eight and countering, blocked by direction. Toby Projective It will be m g. I'll sign off Peter. It's called Toe I in to help no m eight outside or better simplifying this equation, it can be written it by solving this you will, right, Al for Toby de Upon and sign off, Peter, substituting I and simplify, you will get one third off Sinus square theater. So this is the answer off Part eight. No answer off the part. Finding commission off force in the vertical direction. You will get a minus. M d. It's called minus m a. That is minus M l l for why not? Is called You will get MD minus M and L far. We have measured G Beit El Sign off theater upon one third off, and to sign off on solving it, you will get mg upon one plus three Sinus square data in upper direction. That's not for it.

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Vector Mechanics for Engineers: Statics and Dynamics

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Problem

The 10 -lb-uniform rod $A B$ has a total length o…

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Related Courses

Vector Mechanics for Engineers: Statics and Dynamics

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Video Transcript

Ferdinand P. Beer, E. Russell Johnston, Jr., David F. Mazurek

Vector Mechanics for Engineers: Statics and Dynamics

Elyse Gonzalez

Marshall Styczinski

Farnaz Mohseni

Meghan Miholics

This textbook answer is only visible when subscribed! Please subscribe to view the answer

Vector Mechanics for Engineers: Statics and Dynamics

Elyse Gonzalez

Marshall Styczinski

Farnaz Mohseni

Meghan Miholics

Ferdinand P. Beer, E. Russell Johnston, Jr., David F. Mazurek Vector Mechanics for Engineers: Statics and Dynamics

Elyse Gonzalez

Marshall Styczinski

Farnaz Mohseni

Meghan Miholics

Ferdinand P. Beer, E. Russell Johnston, Jr., David F. Mazurek

Vector Mechanics for Engineers: Statics and Dynamics