00:01
Hello everyone, let us see the following question.
00:02
So, there is a reaction sequence given here with the two phenyl rings with intermediate carbonyl group.
00:14
So it is given like this, followed by zinc amalgam and hcl.
00:23
Should be giving us p, followed with socl 2, should be giving us q, followed with n hydras, aluminum chloride should be giving us r.
00:37
So let us see the mechanism.
00:40
So this is clemencean reduction.
00:43
Clemence reduction is specially used to reduce the carbonyl group.
00:48
So this product on clemenzine reaction should give us p.
00:52
So p here is nothing but benzene ring.
00:57
Carbonil group is completely reduced to hydrocarbon and here is a carboxylic group so this is p now this p when treated with socl2 that is a halogenating agent so i am going to remove this and just for my convenience i'll change the position so if this is a ring another ring is this i will take the position to as this c double bond o cl so now this is going to to be treated with anhydrous aluminum chloride.
01:37
So now, anhydrous aluminum chloride will be removing the chlorine.
01:42
Carbon will be positive as an electrophile it substitutes on other benzene ring.
01:47
So the product next to what we should get is already a benzene ring...