Question
The value of $\tan 9^{\circ}-\tan 27^{\circ}-\tan 63^{\circ}+\tan 81^{\circ}$ is(a) 2(b) 3(c) 4(d) 0
Step 1
We can use the property that $\tan(90 - \theta) = \cot(\theta)$ to rewrite $\tan 81^{\circ}$ as $\cot 9^{\circ}$ and $\tan 63^{\circ}$ as $\cot 27^{\circ}$. Show more…
Show all steps
Your feedback will help us improve your experience
Anas Venkitta and 86 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
$$ \tan 9^{\circ}-\tan 27^{\circ}-\tan 63^{\circ}+\tan 81^{\circ}=4 $$
If $\tan A+\cot A=3$ then $\tan ^{3} A+\cot ^{3} A=$ (a) 27 (b) 24 (c) 9 (d) 18
$\tan ^{-1}\left(\frac{1}{4}\right)+\tan ^{-1}\left(\frac{2}{9}\right)$ is equal to: (A) $\frac{1}{2} \cos ^{-1}\left(\frac{3}{5}\right)$ (B) $\frac{1}{2} \sin ^{-1}\left(\frac{3}{5}\right)$ (C) $\frac{1}{2} \tan ^{-1}\left(\frac{3}{5}\right)$ (D) $\tan ^{-1}\left(\frac{1}{2}\right)$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD