Question
The value of the sum $\sum_{n=1}^{13}\left(i^{n}+i^{n+1}\right)$, where $i=\sqrt{-1}$, equals(a) $i$(b) $i-1$(c) $-i$(d) 0
Step 1
We can rewrite this sum as $\sum_{n=1}^{13} i^{n}(1+i)$. Show more…
Show all steps
Your feedback will help us improve your experience
Varsha Aggarwal and 60 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The value of $\sum_{n=1}^{17}\left(i^{n}+i^{n+1}\right)$ is (a) i (b) $\mathrm{i}=1$ (c) -i (d) 0
$\sum\left(\frac{1+i}{1-i \sqrt{3}}\right)^{n}$
COMPLEX NUMBERS
Complex infinite series
. $\sum_{n=1}^{\infty} \frac{(-1)^{n} n}{\sqrt{n^{3}+1}}$
INFINITE SERIES, POWER SERIES
Testing series for convergence; the preliminary test
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD