Question
The value of $x^{2}+2 b x+c$ is positive for all real values of $x$, if(a) $b^{2}-4 c>0$(b) $b^{2}-4 c<0$(c) $c^{2}<b$(d) $b^{2}<c$
Step 1
Step 1: We are given the quadratic equation $x^{2}+2 b x+c$ and we are told that this equation is positive for all real values of $x$. Show more…
Show all steps
Your feedback will help us improve your experience
Anas Venkitta and 66 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Solve for $x$ given that $a$ and $b$ are both positive real numbers. $$\frac{x^{2}+a^{2}}{x^{2}+b^{2}} \geq 0$$
Review: Equations and Inequalities
Inequalities
Solve for $x$ given that $a$ and $b$ are both positive real numbers. $$\frac{x^{2}-b^{2}}{x+b}<0$$
If the roots of the equation $x^{2}-a x+b=0$ are real and differ by a quantity which is less than $c(c>0)$, then $b$ lies between $\frac{a^{2}-c^{2}}{4}$ and $\frac{a^{2}}{4}$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD