00:01
Problem is given that the mass above an equal solution is equal to 19 .5 milligram.
00:12
So, converting that into gram, that's 0 .0195 gram.
00:20
And the volume of the vapor is equal to 1 liter.
00:25
And from the ideal gas equation, pv equal to nrt, we can have p.
00:34
Equal to n, r, t, divided by v.
00:38
But r is the gas constant, and is equal to 0 .0 to 821 liter atmosphere per mole per kelvin.
00:52
And t is the absolute temperature equal to 298 kelvin.
00:58
And n is number of moles of vapor.
01:02
The number of moles is equal to the mass divided by molar mass.
01:08
And we get 0 .0195 gram divided by the molar mass for water is 18 grams per mole.
01:18
And we have the moles equal to 1 .083 times 10 to negative 3 moles.
01:39
So then we substitute these values into the equation, and we get p equal to 1 .083 times 10.
01:50
To the minus 3 times 0 .0821 times 298 divided by v is 1...