Question
The vapor pressure for pure water and pure acetone is measured as a function of temperature. In each case, a graph of the log of the vapor pressure versus 1$/ T$ is found to be a straight line. The slope of the line for water is $-4895 \mathrm{K}$ and the slope of the line for acetone is $-3765 \mathrm{K}$ . Determine $\Delta H_{\mathrm{vap}}$ for each substance. Account for the difference by discussing the molecular structure of the two molecules.
Step 1
303R} \times \frac{1}{T} + \log B \] where P is the vapor pressure, T is the temperature, R is the gas constant, and B is a constant. The slope of the line in the graph of log P versus 1/T represents the term -ΔHvap/(2.303R). Show more…
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The vapor pressure for pure water and pure acetone is measured as a function of temperature. In each case, a graph of the log of the vapor pressure versus 1>T is found to be a straight line. The slope of the line for water is -4895 K, and the slope of the line for acetone is -6748 K. Determine H vap for each substance. Account for the difference by discussing the molecular structure of the two molecules.
The density of acetone vapor in equilibrium with liquid acetone, $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO},$ at $32^{\circ} \mathrm{C}$ is $0.876 \mathrm{g} \mathrm{L}^{-1} .$ What is the vapor pressure of acetone at $32^{\circ} \mathrm{C},$ expressed in kilopascals?
The normal boiling point for acetone is $56.5^{\circ} \mathrm{C}$. At an elevation of $5300 \mathrm{ft}$ the atmospheric pressure is $630 .$ torr. What would be the boiling point of acetone $\left(\Delta H_{\text {vap }}=32.0 \mathrm{~kJ} / \mathrm{mol}\right)$ at this elevation? What would be the vapor pressure of acetone at $25.0^{\circ} \mathrm{C}$ at this elevation?
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