00:03
Okay, let's see if we can figure out this problem.
00:06
We have a volatile liquid and we're told the vapor pressure can be determined by slowly bubbling a known volume of gas through it at a known temperature and pressure.
00:16
So we're given 5 liters of nitrogen is passed through a 7 .2146 gram sample of benzene at 26 degrees celsius.
00:25
The liquid remaining after the experiment has a mass of 5 .1493 grams.
00:30
We're going to assume the gas becomes saturated with benzene vapor and the total gas volume and temperature are constant.
00:38
We're asked to calculate the vapor pressure in torr.
00:44
So first of all, let's find the mass of benzene consumed in the reaction.
00:59
And that will equal 7 .2146 grams minus 5 .1493 grams.
01:09
7 .2146 minus 5 .1493, 2 .0653 grams is used.
01:25
Now let's convert that to moles.
01:30
2 .0653 grams of benzene, which is c6h6, 72, 78 point, i'm going to go to my molar mass calculator.
01:47
Do i have one open? i don't.
01:50
Hang on.
01:51
Lentech molar mass.
01:54
I think it's going to be 78 .12, 78 point, i wonder if benzene is in my list.
02:08
By golly it is.
02:10
This says 78 .11 but i'm going to use 78 .12 because that's what i would make my students use...