We can use the Gram-Schmidt process for this.
We start with $a_{1} = (1,1,0)$. To normalize it, we divide by its length, which is $\sqrt{1^2 + 1^2 + 0^2} = \sqrt{2}$. So, our first basis vector is $u_{1} = \frac{1}{\sqrt{2}}(1,1,0) = (\frac{1}{\sqrt{2}},
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