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The velocity graph of an accelerating car is shown. (a) Use the Midpoint rule to estimate the average velocity of the car during the first 12 seconds. (b) At what time was the instantaneous velocity equal to the average velocity?

a) Average velocity $=45.33 \mathrm{km} / \mathrm{h}$b) $t \approx 5.2$

Calculus 2 / BC

Chapter 6

Applications of Integrals

Section 2

Average Values

Applications of Integration

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using the midpoint rules with an easy people to three. We have the interval from 3 0 to 12 of the T T T is equal to 12 divided by three times via two plus V of six plus V of 10. So using the graft to substitute in values, we end up with that. This is equal to four times 20 plus 50 of 66 which is equal to 544. So therefore, the average philosophy is one over 12 times 544 which is equal to 45 0.33 All right, so that's for party for ah, Part B. We know from part of the average philosophies 45.33 Using the graph, you conceive of the average velocities 45.33 when T is equal to two point of tea years approximately equal to 5.2 seconds

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