Question
The velocity of a particle ( $v$ ) at an instant $t$ is given by $v=a t+b t^{2}$. The dimension of $b$ is(a) [L](b) $\left[\mathrm{LT}^{-1}\right]$(c) $\left[\mathrm{LT}^{-2}\right]$(d) $\left[\mathrm{LT}^{-3}\right]$
Step 1
According to the principle of homogeneity, the dimensions of all terms in an equation must be the same. Therefore, the dimensions of $v$ must be equal to the dimensions of $b t^{2}$. Show more…
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Kinematics
Round 2
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