00:01
So for part a, we're going to use equation 1328.
00:05
And we can then say that here the initial velocity would be equal to the square root of the gravitational constant times m divided by two times the radius of the earth.
00:22
And this would be specific to this problem.
00:26
So using energy conservation, we can then say that's one half m the initial.
00:34
Squared minus the gravitational constant times larger mass times a smaller mass divided by the radius of the earth.
00:43
In this case, the larger mass would be the mass of the earth.
00:47
This would equal negative g times m times m over r.
00:54
So essentially we're just relating, we're just applying rather the law of conservation of energy.
01:00
And then once we plug in our v initial squared, this term essentially becomes we could say one half times m and then multiplied by g times m over 2r sub e minus g times m divided by r sub e this would equal negative g times m m over r and essentially we're trying to solve for r so after algebra algebraically manipulating, we find that r is equaling four thirds times the radius of the earth.
01:44
So essentially, if we wanted to find that ratio, we could say that r over r sub e is equaling 4 over 3...