00:01
For this problem on the topic of geometric optics, we are told that the walls of a prison cell are perpendicular to the four cardinal compass directions.
00:08
Sun enters a rectangular window in the eastern wall and travelled to 0 .37 meters horizontally to shine perpendicular on the wall opposite the window.
00:18
A prisoner is observing the patch of light moving across the western wall, and we need to answer various questions on the system.
00:26
Firstly, we want to know the speed with which the illuminated rectangle will move.
00:34
So we observe the sun moving from east to west across the sky with an angular speed omega of delta theta over delta t, which is 2 pi radiance over 86 ,400 seconds per day, which gives us the angular speed of 7 .2.
01:02
27 times 10 to the minus 5 radiance per second.
01:10
Now the direction of sunlight crossing the cell from the window changes at this rate, moving on the opposite wall at speed v, which is r times omega.
01:21
This is the distance of 2 .37 meters times the angular speed of 7 .27 times 10 to the minus 5, radians per second.
01:36
And so we get the speed at which this rectangular patch moves across the wall to be 0 .172 millimeters per second...