The wave function for the $2 s$ orbital in the hydrogen atom is
$$
\psi_{2 s}=\frac{1}{\sqrt{2 a_{0}^{3}}}\left(1-\frac{\rho}{2}\right) e^{-\rho / 2}
$$
where $a_{0}$ is the value of the radius of the first Bohr orbit, equal to $0.529 \mathrm{~nm}, \rho$ is $Z\left(r / a_{0}\right)$, and $r$ is the distance from the nucleus in meters. Calculate the location of the node of the $2 s$ wave function from the nucleus.