00:01
So we're told that the refractive index of water is 1 .333.
00:09
We have a light beam of wavelength 632 .8 nanometers.
00:18
We want to find out what is the frequency of this beam for problem a.
00:24
So our frequency is given to us by the equation c is equal to the wavelength times the frequency.
00:30
So if it divides c by the wavelength, we should be able to obtain the frequency.
00:36
So 600, so three times 10 to the eighth meters per second over 632 .8 times 10 to the negative 8th meters.
00:54
And that negative 9 is there to account for the nano, because you have to pay attention to your units.
01:00
We'll give us our frequency.
01:02
So our frequency is then equal to 4 .74 times 10 to the negative 14 hertz.
01:33
Oh, just 14, okay, times 10 to the 14 hertz.
01:39
So that's our frequency.
01:41
Now we need to determine what the, that's our answer to a...