00:01
Okay, let's begin solving problem 28.
00:04
First of all, let's set it up.
00:06
We have greetings and we have screen here and we have rich, parallel rays, they pass through the space on the greetings.
00:19
But notice that we don't have a single monochrome light.
00:26
So what we have is the light combined with the wavelength from 380.
00:35
Nanometers to 750 nanometers.
00:47
So that's the range of our lights.
00:51
Of course, they will form some diffraction pattern on our screen here.
00:58
But notice that because the angular position of the grating interference came from the equation 30.
01:10
613, no not 6 .13.
01:14
So which is this b sine theta equals m times lambda.
01:22
So for the same order of the pattern, if we have different wavelength, they will have different theta, which means a screen, for example, if we have red, suppose the 380 is red.
01:40
We might have a first order maximum here.
01:48
But for a blue one, or say a violet one, it might happen here.
02:00
So this is the shift or see the spread of our spectrum on the gradient diffractions...