0:00
All righty.
00:01
So we're going to be solving the system for part a using elimination.
00:07
So i'm going to multiply this top equation by a negative 3 .7.
00:11
And this bottom equation, i'm going to distribute a 3 so we can eliminate the bs first.
00:18
So i'm going to distribute.
00:19
And when i do that, end up getting negative 11 .1b.
00:24
I get negative 13 .69a, and then 105 times negative 3 .7 is negative 388 .50.
00:39
And then down here, when i distribute those, i'm going to end up getting a positive 11 .1b plus a 14 .07a, 123 .9 .9.
00:55
Times 3 is 371 .70.
01:01
So then when we do our elimination, these cancel.
01:05
14 .07, takeaway 13 .69 is 0 .38a.
01:11
And then 371 .7 minus 388 .5 is negative 16 .8.
01:18
When i divide by 0 .38, a is going to be approximately negative 44 .2.
01:25
And then we plug back into one of the original equations.
01:30
So i'm going to do 3b plus 3 .7 times the negative 44 .21 is equal to the 105.
01:43
And when i do that, i have 3b minus 163 .577 equals 105...