Question
The width of a single slit, if the first minimum is observed at an angle of $2^{\circ}$ with a wavelength of light $6980 \AA$ is $\mathrm{mm}$(A) $0.2$(B) $2 \times 10^{-5}$(C) $2 \times 10^{5}$(D) $0.02$
Step 1
We know that 1 Angstrom is equal to $10^{-10}$ meters. So, the wavelength $\lambda$ in meters is given by: \[\lambda = 6980 \times 10^{-10} \, m\] Show more…
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