00:01
So for this question, we've got a nice and complicated drawing.
00:05
So let's start by drawing the picture in the book.
00:11
So we have our system of axes.
00:15
And then we have a circle of radius 1 centered at 1.
00:24
Sorry, 0 .1.
00:26
So this is 2.
00:28
We have a line up here.
00:31
Let's draw that one blue as well.
00:33
So we have the y equals two line.
00:38
And then we are going to construct a points by saying we have this line, which makes an angle t over here.
00:50
Now that gets to some intersection here and here, which allows us to make a point x, y.
01:03
Now the question is, find x, y as functions of t.
01:12
So how are we going to do that? well, we've got a couple of equations that are given to us.
01:23
First of all, oh, many of these points have names.
01:28
So let's do that.
01:29
This one's called o for origin.
01:31
We have a point q over here.
01:35
This red point is point a, i believe.
01:38
No, it's point b.
01:41
This guy is b.
01:43
This guy is a.
01:46
And this point is called p, although we never have a.
01:49
Actually end up using that.
01:51
So first of all, we're told that x is equal to a q.
01:58
Well, i think that much is clear from the drawing.
02:01
We just continue this all the line over.
02:05
This is x.
02:06
Well, it's the same as a q.
02:10
We are furthermore told that y equals to minus a b sign of t.
02:21
Again, i think this should be relatively clear.
02:25
So the distance between a and p, basically because we have congruent triangles, this angle will also be t, and then the right angle triangle over here, a, b, p will give you that this length between a and p is equals to a, b, sine t.
02:47
And then the wide corner, there's just two minus that distance.
02:51
Then third, we have an equality that i'm not sure how to obtain, so i am happy that they tell us, which is ab times origin a equals a q squared, which we know equals x squared.
03:14
So let's try and figure out some stuff.
03:19
So this question takes just a bunch of trial and error.
03:25
You have to find some relations that will eventually help you solve it.
03:30
So the solution is also very much not unique.
03:34
And some will be easier, some will be harder.
03:36
This is the one i found...