Question
The work done by an electric force in moving a charge from point $A$ to point $B$ is $2.70 \times 10^{-3} \mathrm{~J}$. The electric potential difference between the two points is $V_{A}-V_{B}=50.0 \mathrm{~V}$. What is the charge?
Step 1
We are given the work done (2.70 x 10^-3 J) and the potential difference (50.0 V). We need to find the charge q. Rearranging the formula to solve for q, we get: Show more…
Show all steps
Your feedback will help us improve your experience
Delete Me and 97 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The work done by an electric force in moving a charge from point $A$ to point $B$ is $2.70 \times 10^{-3} \mathrm{J}$ . The electric potential difference between the two points is $V_{A}-V_{B}=50.0 \mathrm{V}$ . What is the charge?
The work done by an electric force in moving a charge from point A to point B is 2.5 x 10^-3 J. The electric potential difference between the two points is (VA - VB) = 75 V. What is the charge?
The work done by an electric force in moving a charge from point A to point B is 2.54 × 10⁻³ J. The electric potential difference between the two points is Vₐ – V₂ = 44.5 V. What is the charge? -5.7e-5 C.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD