Question
The work function for potassium is 2.24 eV. If potassium metal is illuminated with light of wavelength $350 \mathrm{nm},$ find $(\mathrm{a})$ the maximum kinetic energy of the photoclectrons and (b) the cutoff wavelength.
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Step 1: The energy of a photon is given by the equation $E = \frac{hc}{\lambda}$, where $h$ is Planck's constant, $c$ is the speed of light, and $\lambda$ is the wavelength of the light. Show more…
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