The Wronskian of a pair of differentiable functions $f(x), g(x)$ is the scalar function
$$
W[f(x), g(x)]=\operatorname{det}\left(\begin{array}{rr}
f(x) & g(x) \\
f^{\prime}(x) & g^{\prime}(x)
\end{array}\right)=f(x) g^{\prime}(x)-f^{\prime}(x) g(x) .
$$
(a) Prove that if $f, g$ are linearly dependent, then $W[f(x), g(x)] \equiv 0$. Hence, if $W[f(x), g(x)] \not \equiv 0$, then $f, g$ are linearly independent. (b) Let $f(x)=x^3, g(x)=|x|^3$. Prove that $f, g \in \mathrm{C}^2$ are twice continuously differentiable and linearly independent, but $W[f(x), g(x)] \equiv 0$. Thus, the Wronskian is not a fool-proof test for linear independence.
Remark. It can be proved, [7], that if $f, g$ both saticfy a secend order linear ordinary differential equation, then Page 123 ir 702 everdent @ And +ly if $W[f(x), g(x)] \equiv 0$.