00:01
In this problem, we're given the x and y components of a position vector, and we're asked to find the magnitude of direction of that position vector.
00:10
So first, we're given that the x component has a magnitude of 125 meters and is in the negative x direction, which means it's at 180 degrees.
00:24
And the y component has a magnitude of 184 meters and is in the negative y direction which is 270 degrees.
00:38
Now we have to remember to find the magnitude of a vector.
00:45
We take the square root of the sum of the squares of its components, so rx squared plus r y squared.
00:53
And to find the direction, we have to take the inverse turet of the sum of the squares of its components, so rx squared, so rx squared plus r x squared, and to find the direction, we have to take the tangent of your y component over your x component...