Question
The Young's modulus of a wire of length $L$ and $r a d$ is $r$ is $Y$. If the length is reduced to $\frac{L}{2}$ and radius is $\frac{r}{2}$ then the Young's modulus will be(a) $\frac{Y}{2}$(b) $Y$(c) $2 Y$(d) $4 Y$
Step 1
Step 1: The Young's modulus of a material is given by the formula $Y = \frac{F/A}{\Delta L/L}$, where $F$ is the force applied, $A$ is the cross-sectional area, $\Delta L$ is the change in length, and $L$ is the original length. Show more…
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The young's modulus of a wire of length $\mathrm{L}$ and radius $\mathrm{r}$ is $\mathrm{Y}\left(\mathrm{N} / \mathrm{m}^{2}\right)$. If the length and radius are reduced to $\mathrm{L} / 2$ and $\mathrm{r} / 2$. Then what will be its young's modulus? (A) $\mathrm{Y} / 2$ (B) $\mathrm{Y}$ (C) $2 \mathrm{Y}$ (D) $4 \mathrm{Y}$
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The Young's modulus of a wire of length L and radius r is Y N/m2. If the length and radius are reduced to L/2 and r/2, then its Young's modulus will be (a) Y/2 (b) Y (c) 2Y (d) 4Y
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