The zirconium oxalate K2 Zr(C2 O4)3(H2 C2 O4) ·H2 O was synthesized by mixing 1.68 g of ZrOCl2

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The zirconium oxalate K2 Zr(C2 O4)3(H2 C2 O4) ·H2 O was...

The zirconium oxalate $\mathrm{K}_{2} \mathrm{Zr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right) \cdot \mathrm{H}_{2} \mathrm{O}$ was synthesized by mixing $1.68 \mathrm{~g}$ of $\mathrm{ZrOCl}_{2} \cdot 8 \mathrm{H}_{2} \mathrm{O}$ with $5.20 \mathrm{~g}$ of $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}$ and an excess of aqueous $\mathrm{KOH}$. After $2 \mathrm{months}$ $1.25 \mathrm{~g}$ of crystalline product was obtained, along with aqueous $\mathrm{KCl}$ and water. Calculate the percent yield.

The zirconium oxalate $\mathrm{K}_{2} \mathrm{Zr}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right) \cdot \mathrm{H}_{2} \mathrm{O}$ was
synthesized by mixing $1.68 \mathrm{~g}$ of $\mathrm{ZrOCl}_{2} \cdot 8 \mathrm{H}_{2} \mathrm{O}$ with $5.20 \mathrm{~g}$ of $\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}$ and an excess of aqueous $\mathrm{KOH}$. After $2 \mathrm{months}$
$1.25 \mathrm{~g}$ of crystalline product was obtained, along with aqueous $\mathrm{KCl}$ and water. Calculate the percent yield.

Key Concepts

Percent Yield

Percent yield is a measure of the efficiency of a chemical reaction and is defined as the ratio of the actual yield to the theoretical yield, multiplied by 100. It is used to assess how close a laboratory synthesis came to the predicted amount based on stoichiometry.

Stoichiometry

Stoichiometry is the quantitative aspect of chemical reactions, using the relationships defined by a balanced chemical equation to relate the amounts of reactants and products. It is essential for calculating theoretical yields and determining the proportions needed for a reaction.

Limiting Reagent

The concept of the limiting reagent involves identifying which reactant in a chemical equation is completely consumed first, thereby limiting the amount of product that can be formed. Determining the limiting reagent is crucial in yield calculations.

Molar Mass Calculation

Molar mass calculation involves determining the mass of one mole of a compound by summing the atomic masses of its constituent elements. This calculation is fundamental for converting between mass and moles, which is necessary in stoichiometric computations.

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