00:01
So we can say for part a, the ratio of the root mean squared speed of the two uranium atoms, we can say that v .s, the root mean squared speed for uranium 235, divided by the root mean squared speed for uranium 238, would be equalling the square root of 3 times k, the boltsman constant, multiplied by the temperature divided by the mass of uranium 235.
00:37
This would be divided by square root of three times boltzmann's constant times the temperature, divided by the mass of uranium 238.
00:48
And so this would be equalling the square root of the mass of uranium 238 divided by the mass of uranium 235.
00:58
And so we can then say that the root, the root, mean squared speed are v rms 235 divided by vs of rms 238 would be equalling essentially square root of 352 grams per mole divided by avagos number this would be divided by the square root of 349 divided by abogado's number and this is equaling 1 .004.
01:42
This would be the required ratio for part a.
01:46
For part b, then, we can say that the root mean squared speeds of the uranium hexafluoride consisting of uranium 235, we can say that vrms for 235 would be equaling 1 .004 times the rms.
02:15
Vrms for 238 and so we can then say that this is going to be equaling vrms times 235 multiplied by vrms for 238 for 238 plus 0 .004 times vrms for 238 and so we can then substitute, let's subtract and say vrms 235 minus vrms 238, equaling 0 .004, vrms 238.
03:13
And we're going to substitute one meter per second for this difference here.
03:19
And then we can substitute in the formula for the root means squared speed.
03:26
And so we can say that then one meter per second is going to be equal to 0 .004 times the square root of 3 times boltzman constant, bultzman's constant times t divided by the mass of uranium 238.
03:44
And so we can say solving for the temperature, this would be equal to 1 meter per.
03:52
Per second divided by .004 quantity squared multiplied by the mass of uranium 238 divided by three times boltzmann's constant and so we can find for part b the temperature t this would be equaling again 1 .00 meters per second divided by point zero zero four quantity squared multiplied by 352 .0 times 10 to the negative third kilograms per mole...