There are two nucleophiles in each of the following reactions: For each reaction, explain why th

step 1 We're going to look at some different reactions. So starting with two methyl propane. Propine. O

There are two nucleophiles in each of the following...

Key Concepts

Major Product Determination

The major product in reactions involving competing nucleophiles is determined by the nucleophile that reacts the most frequently with the electrophile. This predominantly results from kinetic control, where the more concentrated nucleophile, by virtue of its higher collision frequency, drives the formation of the major product.

Reaction Kinetics

The rate of a reaction is influenced by both the intrinsic reactivity of the nucleophile and its concentration in the reaction mixture. Hence, even if one nucleophile is inherently more reactive, the one that is more prevalent can dominate the reaction outcome due to more frequent effective collisions with the electrophile.

Nucleophilicity

Nucleophilicity refers to the inherent ability of a species to donate an electron pair to an electrophile. Although a stronger nucleophile can react more rapidly under identical conditions, its impact may be diminished if present at a lower concentration compared to a weaker but more abundant nucleophile.

Nucleophile Concentration

In reactions where two nucleophiles are present, the one in higher concentration is more likely to collide with and react with the electrophile, despite differences in intrinsic reactivity. This is due to the mass action effect, where a greater number of molecules increases the probability of effective collisions, thereby driving the major reaction pathway.

Transcript

00:01 We're going to look at some different reactions.

00:05 So starting with two methyl propane.

00:08 Propine.

00:11 Okay, so if we react this with some chlorine gas in a solution of ethanol or methanol, what we basically have now is two nucleophiles.

00:25 So we have this ultrine that will first act as a nucleophile to pick up a chlorine atom.

00:32 And then we also have the solvent that can act as nucleophile, since hydroxels are quite, they have some basicity as well as some, you know, um, nucleophilicity.

00:45 All right.

00:46 So being the solvent, this one is at higher concentrations.

00:51 Okay, so that's just the basic thing here.

00:53 Our solvents are at higher concentrations, since they are basically ubiquitous around the whole reaction mixture.

01:01 Okay, so what we'll basically get here is again a carbocadion intermediate, but the one that would be favored is the one that is the most substituted.

01:15 And here, the tertiary site as opposed to the primary site.

01:20 So then with that, our nucleophile can come in and attack at this position basically like so to form our ether product like that.

01:39 So that's just the basic mechanism there.

01:42 So then for the next reaction, we had a propene molecule, so then it would be the exact same.

01:53 Okay, so if we react this, if i believe it was sodium iodide with hbr, and then they put two equivalents of sodium iodide, meaning this one is higher concentration there.

02:13 Now if we just mix all of these two together.

02:17 What basically form is the br first at this site...

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