00:01
Hi guys, since this problem, we have the number of degrees of freedom is n minus 1.
00:08
So n minus 1, it's 16 minus 1, which is 15.
00:13
Okay, so first find the standard error mean.
00:17
So it's equal the standard deviation, which is 4 .61 over the square root of n.
00:29
Okay, so it's 1 .15 to 5 .5.
00:33
Okay, now we have to find out the test statistics, okay, so t equal x -dash minus mu node over an s -e mean.
00:47
Okay, so it's 98 .33 minus 100 over 1 .1525.
01:01
Okay, so t equal negative 1 .449.
01:09
Okay, since the t statistics, we have t of 0 .1 and 15 equals 1 .341, and we have t of 0 .05 and 15.
01:24
And we have t of 0 .05 and 15 equals 1 .753.
01:31
So the test is two -sided.
01:34
Okay.
01:35
Therefore, the p value lies between 0.
01:40
1 and 0 .2...