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Thermography is a technique for measuring radiant heat and detecting variations in surface temperatures that may be medically, environmentally, or militarily meaningful.(a) What is the percent increase in the rate of heat transfer by radiation from a given area at a temperature of $34.0^{\circ} {C}{C}$ compared with that at $33.0^{\circ} {C}$, such as on a person’s skin? (b) What is the percent increase in the rate of heat transfer by radiation from a given area at a temperature of 34.0oC compared with that at $20.0^{\circ} {C}$ , such as for warm and cool automobile hoods?

a)1.31 percentb)20. 53 percent

Physics 101 Mechanics

Chapter 14

Heat and Heat Transfer Methods

Thermal Properties of Matter

Cornell University

Rutgers, The State University of New Jersey

Hope College

University of Winnipeg

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So just all this question. We must convert temperature to the proper unit that is killed because now we are going to use absolute values instead of fusing different. So temperature one is, as the question says is, 34 degrees says yes. In terms of Kelvin, that would be 34 plus 2 73 that is 307 Kelvin T too, which is 33 degree Celsius. Will be 306 Kelvin No, we know that rate off he transfer. So let's say this is Kyu won by t on cue to buy tea. So I'm taking ratio directly since we know the formula is Sigma, that is Stephen Bozeman Constant area the area off so any of surface on DDE M acidity and temperature to the powerful. Since we're using same material and same object, all these three quantities will be saying so. Sigma a Absalon again for Q two. But the temperature is different, so this is simply 307 to the four divided by 306 to the food. Now let's calculate that he's, you know, seven four divided by he's your six hour four. That gives me 1.0 see, I'm sorry about that. One three one full. Now we are asked to find the percent increase. So percent increase is equal to Q one by t that we do that again. Kill one Divided by T minus Q two Divided by t divided by Q to buy tea que tu by teeth since Q to his initial, that is 33 degrees Celsius was in issue. Uh, this is the Formula Times 100. No, we know that Q. One times Cuban by tease 1.1314 times Cue to leave our invitee so the difference will just yield. So if we substitute key one divided by two in terms of Q two divided by T, it will just look like this. So the answer here is one point 314 present, so the percent increases 1.3% Now, in part B, we are given the initial temperature is 20 degrees, so procedure is again the same. So we'll find in this case Ki won by T again divided by Q to buy tea. But the procedure is that we are We are to compare 34 degrees Celsius, that is 307 Kelvin to 20 degrees since years which is 2 93 children. So let's do that. Calculation 304 s o B 07 to the fore. You got it. Bye to 93 four. So the answer here is one point twos You five feet again. If you do the same procedure, percent increase. If you use the same formula and substitute Ki won by t in terms of queue to buy tea, you will get the answer is 0.2053 times 100 which is equal to 20.53 So the percent increase now is very high. You can see it's 20.53 Thank you for listening.

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